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COMEDK · Maths · 34. Three Dimensional Geometry

The measure of the angle between the lines \(x=k+1, \quad y=2 k-1, \quad z=2 k+3, \quad k \in R \quad\) and \(\quad \dfrac{x-1}{2}=\dfrac{y+1}{1}=\dfrac{z-1}{-2}\) is

  1. A \(\sin ^{-1}\left(\dfrac{4}{3}\right)\)
  2. B \(\cos ^{-1}\left(\dfrac{4}{9}\right)\)
  3. C \(\sin ^{-1}\left(\dfrac{\sqrt{5}}{3}\right)\)
  4. D \(\dfrac{\pi}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\dfrac{\pi}{2}\)

Step-by-step Solution

Detailed explanation

The first line is given by \(x = k+1\), \(y = 2k-1\), \(z = 2k+3\). This can be written in symmetric form as \(\dfrac{x-1}{1} = \dfrac{y+1}{2} = \dfrac{z-3}{2} = k\). The direction vector of this line is \(\vec{v_1} = \hat{i} + 2\hat{j} + 2\hat{k}\). The second line is given by…
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