COMEDK · Maths · 34. Three Dimensional Geometry
The lines \(\frac{x-1}{2}=\frac{y-4}{4}=\frac{z-2}{3}\) and \(\frac{1-x}{1}=\frac{y-2}{5}=\frac{3-z}{a}\) are perpendicular to each other, then \(a\) equals to
- A -6
- B 6
- C \(\frac{22}{3}\)
- D \(-\frac{22}{3}\)
Answer & Solution
Correct Answer
(B) 6
Step-by-step Solution
Detailed explanation
Let \(L_1: \frac{x-1}{2}=\frac{y-4}{4}=\frac{z-2}{3}\) and \(L_2=\frac{1-x}{1}=\frac{y-2}{5}=\frac{3-z}{a}\) the line \(L_2\) can be written as \(\frac{x-1}{-1}=\frac{y-2}{5}=\frac{z-3}{-a}\) Now, the DR's of lines \(L_1\) and \(L_2\) are \((2,4,3)\) and \((-1,5,-a)\)…
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