COMEDK · Maths · 34. Three Dimensional Geometry
The lines \(\dfrac{x-1}{2}=\dfrac{y-4}{4}=\dfrac{z-2}{3}\) and \(\dfrac{1-x}{1}=\dfrac{y-2}{5}=\dfrac{3-z}{a}\) are perpendicular to each other, then \(a\) equals to
- A \(-6\)
- B 6
- C \(\dfrac{22}{3}\)
- D \(-\dfrac{22}{3}\)
Answer & Solution
Correct Answer
(B) 6
Step-by-step Solution
Detailed explanation
The first line is given by \(\dfrac{x-1}{2} = \dfrac{y-4}{4} = \dfrac{z-2}{3}\). The direction vector of this line is \(\vec{v_1} = 2\hat{i} + 4\hat{j} + 3\hat{k}\). The second line is given by \(\dfrac{1-x}{1} = \dfrac{y-2}{5} = \dfrac{3-z}{a}\). Rewriting this in standard form…
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