COMEDK · Maths · 12. Circle
The length of \(y\)-intercept of the circle \(x^2+y^2-6 x+4 y+3=0\) is
- A 2
- B \(2 \sqrt{2}\)
- C \(2 \sqrt{7}\)
- D \(2 \sqrt{6}\)
Answer & Solution
Correct Answer
(A) 2
Step-by-step Solution
Detailed explanation
General equation of circle is \(x^2+y^2+2 g x+2 f y+c=0\) On comparing with given equation \(x^2+y^2-6 x+4 y+3=0\), we get \(\begin{aligned} g & =-3 \\ f & =2 \\ c & =3 \\ y \text {-intercept } & =2 \sqrt{f^2-c} \\ & =2 \sqrt{4-3}=2 \sqrt{1}=2 \end{aligned}\)
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