COMEDK · Maths · 34. Three Dimensional Geometry
The length of the perpendicular from the point \(P(1,-1,2)\) to the given line \(\dfrac{x+1}{2}=\dfrac{y-2}{-3}=\dfrac{z+2}{4}\) is
- A \(\sqrt{21}\) units
- B \(\sqrt{29}\) units
- C \(\sqrt{6}\) units
- D 0 units
Answer & Solution
Correct Answer
(D) 0 units
Step-by-step Solution
Detailed explanation
Let the line be \(L: \dfrac{x+1}{2} = \dfrac{y-2}{-3} = \dfrac{z+2}{4} = \lambda\). Any point \(Q\) on the line \(L\) is given by \(Q(2\lambda - 1, -3\lambda + 2, 4\lambda - 2)\). The vector \(\overrightarrow{PQ}\) is given by…
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