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COMEDK · Maths · 5. Sequences and Series

The last digit of \(\sum_{\substack{1 < p < 100 \\ p \rightarrow \text { prime }}} p !-\sum_{n=1}^{50}(2 n) !\) is

  1. A 2
  2. B 4
  3. C 6
  4. D 8
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Answer & Solution

Correct Answer

(A) 2

Step-by-step Solution

Detailed explanation

\(\underset{\substack{1 < p < 100 \\ p \rightarrow p r i m e}}{ } P !-\sum_{n=1}^{50}(2 n !)=(2 !+3 !+5 !+7 !+\ldots)\) \(-(2 !+4 !+6 !+\ldots)\) After 5 ! the number will have 0 at the one's place. So, they will no effect the last digit of the total sum. Now last digit of…
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