COMEDK · Maths · 34. Three Dimensional Geometry
The image of a point \(P(3,5,3)\) in the line \(\dfrac{x}{1}=\dfrac{y-1}{2}=\dfrac{z-2}{3}\) is \(P^{\prime}(a, b, c)\). Then \(a+b+c=\)
- A \(-7\)
- B \(7\)
- C \(-17\)
- D \(3\)
Answer & Solution
Correct Answer
(B) \(7\)
Step-by-step Solution
Detailed explanation
Let the line be \(L: \dfrac{x}{1} = \dfrac{y-1}{2} = \dfrac{z-2}{3} = k\). Any point \(Q\) on the line is given by \(Q(k, 2k+1, 3k+2)\). The direction vector of the line is \(\vec{v} = \hat{i} + 2\hat{j} + 3\hat{k}\). The vector…
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