COMEDK · Maths · 32. Differential Equations
The general solution of the differential equation \(\frac{d y}{d x}+\frac{1+\cos 2 y}{1-\cos 2 y}=0\) is given by
- A \(\tan y+\cot x=c\)
- B \(\tan y-\cot x=c\)
- C \(\tan x-\cot y=c\)
- D \(\tan x+\cot x=c\)
Answer & Solution
Correct Answer
(B) \(\tan y-\cot x=c\)
Step-by-step Solution
Detailed explanation
We have, \(\quad \frac{d y}{d x}+\frac{1+\cos 2 y}{1-\cos 2 x}=0\) \(\Rightarrow \quad \quad \frac{d y}{d x}=-\left(\frac{1+\cos 2 y}{1-\cos 2 x}\right)\) \(\Rightarrow \quad \quad \frac{d y}{d x}=-\frac{2 \cos ^{2} y}{2 \sin ^{2} x}\)…
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