COMEDK · Maths · 32. Differential Equations
The general solution of \(\left(\frac{d y}{d x}\right)^2=1-x^2-y^2+x^2 y^2\) is
- A \(2 \sin ^{-1} y=x \sqrt{1-x^2}+\sin ^{-1} x+C\)
- B \(\cos ^{-1} y=x \cos ^{-1} x\)
- C \(\sin ^{-1} y=\frac{1}{2} \sin ^{-1} x+C\)
- D \(2 \sin ^{-1} y=x \sqrt{1-y^2}+C\)
Answer & Solution
Correct Answer
(A) \(2 \sin ^{-1} y=x \sqrt{1-x^2}+\sin ^{-1} x+C\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \text { Given, }\left(\frac{d y}{d x}\right)^2=1-x^2-y^2+x^2 y^2 \\ & \Rightarrow \quad\left(\frac{d y}{d x}\right)^2=\left(1-y^2\right)-x^2\left(1-y^2\right)=\left(1-x^2\right)\left(1-y^2\right) \\ & \therefore \quad \frac{d y}{d…
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