COMEDK · Maths · 32. Differential Equations
The general solution of \(\left(\dfrac{d y}{d x}\right)^2=1-x^2-y^2+x^2 y^2\) is
- A \(\sin ^{-1} y=\dfrac{1}{2} \sin ^{-1} x+C\)
- B \(2 \sin ^{-1} y=x \sqrt{1-x^2}+\sin ^{-1} x+C\)
- C \(\cos ^{-1} y=x \cos ^{-1} x\)
- D \(2 \sin ^{-1} y=x \sqrt{1-y^2}+C\)
Answer & Solution
Correct Answer
(B) \(2 \sin ^{-1} y=x \sqrt{1-x^2}+\sin ^{-1} x+C\)
Step-by-step Solution
Detailed explanation
\(\left(\dfrac{dy}{dx}\right)^2 = (1-x^2)(1-y^2)\) Separating variables: \(\dfrac{dy}{\sqrt{1-y^2}} = \sqrt{1-x^2}\ dx\) Integrating both sides: \(\sin^{-1}y = \dfrac{x}{2}\sqrt{1-x^2} + \dfrac{1}{2}\sin^{-1}x + C_1\) Multiplying by 2:…
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