COMEDK · Maths · 32. Differential Equations
\(\text { The general solution of } \dfrac{d y}{d x}=\sin ^{-1} x \text { is }\)
- A \(y=x \sin ^{-1} x-\sqrt{1-x^2}+C\)
- B \(y=x \sin ^{-1} x+\sqrt{1-x^2}+C\)
- C \(y=-x \sin ^{-1} x+\sqrt{1-x^2}+C\)
- D \(y=-x \sin ^{-1} x-\sqrt{1-x^2}+C\)
Answer & Solution
Correct Answer
(B) \(y=x \sin ^{-1} x+\sqrt{1-x^2}+C\)
Step-by-step Solution
Detailed explanation
The given differential equation is \(\dfrac{dy}{dx} = \sin^{-1} x\). Integrating both sides with respect to \(x\), we get \(y = \int \sin^{-1} x \, dx\). Using integration by parts, let \(u = \sin^{-1} x\) and \(dv = dx\). Then \(du = \dfrac{1}{\sqrt{1-x^2}} dx\) and \(v = x\).…
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