COMEDK · Maths · 28. Indefinite Integration
The function \(y=\dfrac{\log x}{x^3}\) is strictly increasing function for
- A \(x > e^{\dfrac{1}{3}}\)
- B \(x < 2\)
- C \(x < e^{\dfrac{1}{3}}\)
- D \(0 < x < e^{\dfrac{1}{3}}\)
Answer & Solution
Correct Answer
(D) \(0 < x < e^{\dfrac{1}{3}}\)
Step-by-step Solution
Detailed explanation
Given the function \(y = \dfrac{\log x}{x^3}\), we find its derivative with respect to \(x\) using the quotient rule. \(\dfrac{dy}{dx} = \dfrac{x^3 \cdot \dfrac{d}{dx}(\log x) - \log x \cdot \dfrac{d}{dx}(x^3)}{(x^3)^2}\)…
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