COMEDK · Maths · 24. Functions
The function \(f: \mathbb{R} \to \mathbb{R}\) defined by \(f(x) = \dfrac{x}{x^2+1}\ \forall x \in \mathbb{R}\) is
- A One-one but not onto
- B Onto but not one-one
- C One-one and onto
- D Neither one-one nor onto
Answer & Solution
Correct Answer
(D) Neither one-one nor onto
Step-by-step Solution
Detailed explanation
Given \(f(x) = \dfrac{x}{x^2+1}\) To check for one-one, let \(f(x_1) = f(x_2)\) \(\dfrac{x_1}{x_1^2+1} = \dfrac{x_2}{x_2^2+1}\) \(x_1 x_2^2 + x_1 = x_2 x_1^2 + x_2\) \(x_1 x_2(x_2 - x_1) - (x_2 - x_1) = 0\) \((x_2 - x_1)(x_1 x_2 - 1) = 0\) This gives \(x_1 = x_2\) or…
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