COMEDK · Maths · 25. Continuity and Differentiability
\(\text { The function defined by } f(x)=\left\{\begin{array}{cc}
\dfrac{\sin x}{x}+\cos x & x>0 \\
-5 k & x=0 \\
\dfrac{4(1-\sqrt{1-x})}{x} & x<0
\end{array} \quad \text { is continous at } x=0, \quad \text { then } k\right. \text { equals }\)
- A \(-\dfrac{2}{5}\)
- B 2
- C \(-2\)
- D \(-\dfrac{5}{2}\)
Answer & Solution
Correct Answer
(A) \(-\dfrac{2}{5}\)
Step-by-step Solution
Detailed explanation
For the function \(f(x)\) to be continuous at \(x = 0\), the left-hand limit, right-hand limit, and the value of the function at \(x = 0\) must be equal. The right-hand limit is given by…
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