COMEDK · Maths · 34. Three Dimensional Geometry
The foot of the perpendicular from the point \(P(1,6,3)\) to the line \(\dfrac{x}{1}=\dfrac{y-1}{2}=\dfrac{2-z}{-3}\) is
- A \((-1,-1,-1)\)
- B \((0,-3,2)\)
- C \((-2,-7,-4)\)
- D \((1,3,5)\)
Answer & Solution
Correct Answer
(D) \((1,3,5)\)
Step-by-step Solution
Detailed explanation
The given line is \(\dfrac{x}{1} = \dfrac{y-1}{2} = \dfrac{z-2}{3} = \lambda\). Any point on the line is given by \(Q(\lambda, 2\lambda + 1, 3\lambda + 2)\). The vector…
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