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COMEDK · Maths · 34. Three Dimensional Geometry

The foot of the perpendicular from the point \(P(1,6,3)\) to the line \(\dfrac{x}{1}=\dfrac{y-1}{2}=\dfrac{2-z}{-3}\) is

  1. A \((-1,-1,-1)\)
  2. B \((0,-3,2)\)
  3. C \((-2,-7,-4)\)
  4. D \((1,3,5)\)
Verified Solution

Answer & Solution

Correct Answer

(D) \((1,3,5)\)

Step-by-step Solution

Detailed explanation

The given line is \(\dfrac{x}{1} = \dfrac{y-1}{2} = \dfrac{z-2}{3} = \lambda\). Any point on the line is given by \(Q(\lambda, 2\lambda + 1, 3\lambda + 2)\). The vector…