COMEDK · Maths · 15. Hyperbola
The equation to the normal to the hyperbola \(\frac{x^{2}}{16}-\frac{y^{2}}{9}=1\) at \((-4,0)\) is
- A \(2 x-3 y=1\)
- B \(x=0\)
- C \(x=1\)
- D \(y=0\)
Answer & Solution
Correct Answer
(D) \(y=0\)
Step-by-step Solution
Detailed explanation
We have, \[ \frac{x^{2}}{16}-\frac{y^{2}}{9}=1 \] Since, \((-4,0)\) is vertex of the hyperbola, so equation of normal at \((-4,0)\) is \(y=0\).
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