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COMEDK · Maths · 15. Hyperbola

The equation to the normal to the hyperbola \(\frac{x^{2}}{16}-\frac{y^{2}}{9}=1\) at \((-4,0)\) is

  1. A \(2 x-3 y=1\)
  2. B \(x=0\)
  3. C \(x=1\)
  4. D \(y=0\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(y=0\)

Step-by-step Solution

Detailed explanation

We have, \[ \frac{x^{2}}{16}-\frac{y^{2}}{9}=1 \] Since, \((-4,0)\) is vertex of the hyperbola, so equation of normal at \((-4,0)\) is \(y=0\).