COMEDK · Maths · 12. Circle
The equation of the smallest circle passing through the points \((2,2)\) and \((3,3)\) is
- A \(x^{2}+y^{2}+5 x+5 y+12=0\)
- B \(x^{2}+y^{2}-5 x-5 y+12=0\)
- C \(x^{2}+y^{2}+5 x-5 y+12=0\)
- D \(x^{2}+y^{2}-5 x+5 y-12=0\)
Answer & Solution
Correct Answer
(B) \(x^{2}+y^{2}-5 x-5 y+12=0\)
Step-by-step Solution
Detailed explanation
(a) Put \(x=2, y=2\), we have \[ \begin{aligned} &(2)^{2}+(2)^{2}+5 \times 2+5 \times 2+12 \\ &\quad=4+4+10+10+12=40 \neq 0 \end{aligned} \] (b) Put \(x=2, y=2\), we have \[ \begin{aligned} (2)^{2}+(2)^{2}-5 \times 2-5 \times 2+12 \\ =& 4+4-10-10+12=0 \end{aligned} \] Put…
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