COMEDK · Maths · 15. Hyperbola
The equation of the director circle of the hyperbola \(\frac{x^{2}}{16}-\frac{y^{2}}{4}=1\) is given by
- A \(x^{2}+y^{2}=16\)
- B \(x^{2}+y^{2}=4\)
- C \(x^{2}+y^{2}=20\)
- D \(x^{2}+y^{2}=12\)
Answer & Solution
Correct Answer
(D) \(x^{2}+y^{2}=12\)
Step-by-step Solution
Detailed explanation
Equation of director circle of hyperbola, \(\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1\) is \(x^{2}+y^{2}=a^{2}-b^{2}\) Hence, director circle of \(\frac{x^{2}}{16}-\frac{y^{2}}{4}=1\) is \[ x^{2}+y^{2}=16-4 \Rightarrow x^{2}+y^{2}=12 \]
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