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COMEDK · Maths · 14. Ellipse

The equation of an ellipse, whose focus is \((1,0)\), directrix is \(x=4\) and whose eccentricity is a root of the quadratic equation \(2 x^2-3 x+1=0\), is

  1. A \(\dfrac{x^2}{3}+\dfrac{y^2}{8}=1\)
  2. B \(\dfrac{x^2}{4}+\dfrac{y^2}{3}=1\)
  3. C \(\dfrac{x^2}{3}+\dfrac{y^2}{4}=1\)
  4. D \(\dfrac{x^2}{2}+\dfrac{y^2}{3}=1\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\dfrac{x^2}{4}+\dfrac{y^2}{3}=1\)

Step-by-step Solution

Detailed explanation

The given quadratic equation is \(2e^2 - 3e + 1 = 0\). Solving for \(e\): \(2e^2 - 2e - e + 1 = 0 \Rightarrow 2e(e - 1) - 1(e - 1) = 0 \Rightarrow (2e - 1)(e - 1) = 0\). The roots are \(e = 1\) or \(e = 1/2\). Since the curve is an ellipse, \(e < 1\), so \(e = 1/2\). Let the…