COMEDK · Maths · 12. Circle
The equation of a circle passing through the origin is \(x^2+y^2-6 x+2 y=0\). The equation of one of its diameter is
- A \(x-3 y=0\)
- B \(x+3 y=0\)
- C \(x+y=0\)
- D \(3 x-y=0\)
Answer & Solution
Correct Answer
(B) \(x+3 y=0\)
Step-by-step Solution
Detailed explanation
The given equation of the circle is \(x^2 + y^2 - 6x + 2y = 0\). Comparing this with the general equation of a circle \(x^2 + y^2 + 2gx + 2fy + c = 0\), we have \(2g = -6\) and \(2f = 2\). Thus, \(g = -3\) and \(f = 1\). The center of the circle is \((-g, -f) = (3, -1)\). A…
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