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COMEDK · Maths · 15. Hyperbola

The ellipse \(\frac{x^{2}}{25}+\frac{y^{2}}{16}=1\) and the hyperbola \(\frac{x^{2}}{25}-\frac{y^{2}}{16}=1\) have in common

  1. A centre and vertices only
  2. B centre, foci and vertices
  3. C centre, foci and directrices
  4. D centre only
Verified Solution

Answer & Solution

Correct Answer

(A) centre and vertices only

Step-by-step Solution

Detailed explanation

Equation of ellipse is \(\frac{x^{2}}{25}+\frac{y^{2}}{16}=1, a>b\) and equation of hyperbola is \(\frac{x^{2}}{25}-\frac{y^{2}}{16}=1, a>b\) Let \(e\) and \(e^{\prime}\) be the eccentricities of the ellipse and hyperbola. So,…