COMEDK · Maths · 15. Hyperbola
The ellipse \(\frac{x^{2}}{25}+\frac{y^{2}}{16}=1\) and the hyperbola \(\frac{x^{2}}{25}-\frac{y^{2}}{16}=1\) have in common
- A centre and vertices only
- B centre, foci and vertices
- C centre, foci and directrices
- D centre only
Answer & Solution
Correct Answer
(A) centre and vertices only
Step-by-step Solution
Detailed explanation
Equation of ellipse is \(\frac{x^{2}}{25}+\frac{y^{2}}{16}=1, a>b\) and equation of hyperbola is \(\frac{x^{2}}{25}-\frac{y^{2}}{16}=1, a>b\) Let \(e\) and \(e^{\prime}\) be the eccentricities of the ellipse and hyperbola. So,…
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