COMEDK · Maths · 10. Straight Lines
The distance of the point \((3,4)\) from the line \(3 x+2 y+7=0\) measured along the line parallel to \(y-2 x+7=0\) is equal to
- A \(\frac{24 \sqrt{5}}{7}\)
- B \(3 \sqrt{5}\)
- C \(\frac{23 \sqrt{5}}{7}\)
- D \(4 \sqrt{5}\)
Answer & Solution
Correct Answer
(A) \(\frac{24 \sqrt{5}}{7}\)
Step-by-step Solution
Detailed explanation
The slope of the line, \(y-2 x+7=0\) \(\begin{array}{ll} \Rightarrow \quad y =2 x-7 \\ \text { Slope } \quad(m) =2 \\ \therefore \text { Slope of } P Q =m_{P Q}=2 \\ \text { Equation of } P Q & \end{array}\) \((y-4)=2(x-3)\) On putting, the value of \(y\) in Eq. (ii), we get…
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