COMEDK · Maths · 10. Straight Lines
The distance of the point \((3,4)\) from the line \(3 x+2 y+7=0\) measured along the line parallel to \(y-2 x+7=0\) is equal to
- A \(\dfrac{23 \sqrt{5}}{7}\)
- B \(4 \sqrt{5}\)
- C \(3 \sqrt{5}\)
- D \(\dfrac{24 \sqrt{5}}{7}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{24 \sqrt{5}}{7}\)
Step-by-step Solution
Detailed explanation
The given point is \(P(3, 4)\) and the line is \(L: 3x + 2y + 7 = 0\). The line along which the distance is measured is parallel to \(y - 2x + 7 = 0\), which has a slope \(m = 2\). The equation of the line passing through \((3, 4)\) with slope \(m = 2\) is given by…
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