COMEDK · Maths · 10. Straight Lines
The distance of the point \((1,2)\) from the line \(x+y+5=0\) measured along the line parallel to \(3 x-y=7\) is equal to
- A \(4 \sqrt{10}\)
- B 40
- C \(\sqrt{40}\)
- D \(10 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(\sqrt{40}\)
Step-by-step Solution
Detailed explanation
The line passing through the point \(P(1, 2)\) and parallel to the line \(3x - y = 7\) has a slope \(m = 3\). The equation of this line is \(y - 2 = 3(x - 1)\), which simplifies to \(y - 2 = 3x - 3\), or \(3x - y - 1 = 0\). To find the intersection point \(Q\) of the lines…
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