COMEDK · Maths · 10. Straight Lines
The distance of the point \((1,2)\) from the line \(x+y+2=0\) measured along the line parallel to \(2 x-y=5\) is equal to
- A \(\dfrac{125}{3}\)
- B \(\dfrac{125}{\sqrt{3}}\)
- C \(\dfrac{5 \sqrt{5}}{3}\)
- D \(\dfrac{5 \sqrt{3}}{3}\)
Answer & Solution
Correct Answer
(C) \(\dfrac{5 \sqrt{5}}{3}\)
Step-by-step Solution
Detailed explanation
The given point is \(P(1, 2)\) and the line is \(L: x + y + 2 = 0\). The line passing through \(P(1, 2)\) and parallel to \(2x - y = 5\) has a slope \(m = 2\). The equation of this line is \(y - 2 = 2(x - 1)\), which simplifies to \(y = 2x\) or \(2x - y = 0\). To find the…
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