COMEDK · Maths · 32. Differential Equations
The degree of the differential equation \(\sqrt{1 + \left(\dfrac{dy}{dx}\right)^{1/3}} = \dfrac{d^2y}{dx^2}\) is:
- A \(3\)
- B \(1\)
- C \(2\)
- D \(6\)
Answer & Solution
Correct Answer
(D) \(6\)
Step-by-step Solution
Detailed explanation
Given differential equation is \(\sqrt{1 + \left(\dfrac{dy}{dx}\right)^{1/3}} = \dfrac{d^2y}{dx^2}\) Squaring both sides, we get \(1 + \left(\dfrac{dy}{dx}\right)^{1/3} = \left(\dfrac{d^2y}{dx^2}\right)^2\) Rearranging the terms,…
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