COMEDK · Maths · 27. Application of Derivatives
The curve \(a x^3+b x^2+c x+d\) has a point of minima at \(x=1\), then
- A \(3 a+b <0\)
- B \(3 a+b>0\)
- C \(a+3 b>0\)
- D \(3 a+b=0\)
Answer & Solution
Correct Answer
(B) \(3 a+b>0\)
Step-by-step Solution
Detailed explanation
Let \(f(x) = ax^3 + bx^2 + cx + d\). The derivative is given by \(f'(x) = 3ax^2 + 2bx + c\). Since the curve has a point of minima at \(x=1\), we must have \(f'(1) = 0\). Thus, \(3a(1)^2 + 2b(1) + c = 0\), which implies \(3a + 2b + c = 0\). For a local minimum at \(x=1\), the…
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