COMEDK · Maths · 34. Three Dimensional Geometry
The coordinates of the vertices of the triangle are \(A(-2,3,6), B(-4,4,9)\) and \(C(0,5,8)\). The direction cosines of the median \(\mathrm{BE}\) are
- A \(\left\langle-\dfrac{3}{\sqrt{13}}, \quad 0, \quad-\dfrac{2}{\sqrt{13}}\right\rangle\)
- B \(\left\langle\dfrac{3}{\sqrt{13}}, \quad 0, \quad-\dfrac{2}{\sqrt{13}}\right\rangle\)
- C \(\left\langle\dfrac{3}{4}, \quad 0, \quad-\dfrac{2}{4}\right\rangle\)
- D \(\left\langle 1, \quad 0, \quad-\dfrac{2}{3}\right\rangle\)
Answer & Solution
Correct Answer
(B) \(\left\langle\dfrac{3}{\sqrt{13}}, \quad 0, \quad-\dfrac{2}{\sqrt{13}}\right\rangle\)
Step-by-step Solution
Detailed explanation
The median BE connects vertex B to the midpoint E of side AC. The coordinates of A are \((-2, 3, 6)\) and C are \((0, 5, 8)\). The midpoint E of AC is given by \(E = \left( \dfrac{-2 + 0}{2}, \dfrac{3 + 5}{2}, \dfrac{6 + 8}{2} \right) = (-1, 4, 7)\). The vector…
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