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COMEDK · Maths · 3. Complex Number

The conjugate of \(z = \dfrac{(4 + i)(1 - i)}{(1 + i)(2 - i)}\)

  1. A \(\dfrac{1}{2} + \dfrac{1}{2} i\)
  2. B \(\dfrac{6}{5} + \dfrac{7}{5} i\)
  3. C \(\dfrac{6}{5} - \dfrac{7}{5} i\)
  4. D \(\dfrac{1}{2} - \dfrac{1}{2} i\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\dfrac{6}{5} + \dfrac{7}{5} i\)

Step-by-step Solution

Detailed explanation

\(z = \dfrac{(4 + i)(1 - i)}{(1 + i)(2 - i)}\) Simplifying the numerator and denominator: \((4 + i)(1 - i) = 4 - 4i + i - i^2 = 5 - 3i\) \((1 + i)(2 - i) = 2 - i + 2i - i^2 = 3 + i\) Substituting these values: \(z = \dfrac{5 - 3i}{3 + i}\) Multiplying the numerator and…