COMEDK · Maths · 7. Binomial Theorem
The coefficient of the third term in the expansion of \(\left(x^2-\dfrac{1}{4}\right)^n\), when expanded in the descending power of \(x\) is 31, then \(n\) is
- A 16
- B 30
- C 32
- D 31
Answer & Solution
Correct Answer
(C) 32
Step-by-step Solution
Detailed explanation
The general term in the expansion of \((x^2 - \dfrac{1}{4})^n\) is given by \(T_{r+1} = ^{n}C_{r} (x^2)^{n-r} (-\dfrac{1}{4})^r\). The third term corresponds to \(r = 2\). \(T_{3} = ^{n}C_{2} (x^2)^{n-2} (-\dfrac{1}{4})^2 = ^{n}C_{2} x^{2n-4} (\dfrac{1}{16})\). The coefficient…
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