COMEDK · Maths · 12. Circle
The circles \(a x^{2}+a y^{2}+2 g_{1} x+2 f_{1} y+c_{1}=0\) and \(b x^{2}+b y^{2}+2 g_{2} x+2 f_{2} y+c_{2}=0\) \((a \neq 0\) and \(b \neq 0)\) cut orthogonally if
- A \(g_{1} g_{2}+f_{1} f_{2}=c_{1}+c_{2}\)
- B \(b g_{1} g_{2}+a f_{1} f_{2}=b c_{1}+a c_{2}\)
- C \(2(g_{1} g_{2}+f_{1} f_{2})=b c_{1}+a c_{2}\)
- D \(g_{1} g_{2}+f_{1} f_{2}=a c_{1}+b c_{2}\)
Answer & Solution
Correct Answer
(C) \(2(g_{1} g_{2}+f_{1} f_{2})=b c_{1}+a c_{2}\)
Step-by-step Solution
Detailed explanation
Given equation of circles are \(a x^{2}+a y^{2}+2 g_{1} x+2 f_{1} y+c_{1}=0\) and \(b x^{2}+b y^{2}+2 g_{2} x+2 f_{2} y+c_{2}=0\) It can be rewritten as, \(x^{2}+y^{2}+\frac{2 g_{1}}{a} x+\frac{2 f_{1}}{a} y+\frac{c_{1}}{a}=0\) and…
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