COMEDK · Maths · 12. Circle
The circle \(x^2+y^2+4 x-7 y+12=0\) cuts an intercept on \(Y\)-axis of length
- A 3
- B 4
- C 7
- D 1
Answer & Solution
Correct Answer
(D) 1
Step-by-step Solution
Detailed explanation
The equation of the circle is \(x^2 + y^2 + 4x - 7y + 12 = 0\). To find the intercept on the Y-axis, set \(x = 0\) in the equation of the circle. \(0^2 + y^2 + 4(0) - 7y + 12 = 0\) \(y^2 - 7y + 12 = 0\) Factoring the quadratic equation, we get \((y - 3)(y - 4) = 0\). The roots…
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