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COMEDK · Maths · 28. Indefinite Integration

The area of the region bounded by the ellipse \(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\) is

  1. A \(\pi a b^2\) sq units
  2. B \(\pi a b\) sq units
  3. C \(\pi^2 a b\) sq units
  4. D \(\pi a^2 b\) sq units
Verified Solution

Answer & Solution

Correct Answer

(B) \(\pi a b\) sq units

Step-by-step Solution

Detailed explanation

The equation of the ellipse is \(\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1\). Solving for \(y\), we get \(y = \pm \dfrac{b}{a} \sqrt{a^2 - x^2}\). The area \(A\) of the ellipse is given by \(4 \times \int_{0}^{a} y \, dx = 4 \int_{0}^{a} \dfrac{b}{a} \sqrt{a^2 - x^2} \, dx\).…
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