COMEDK · Maths · 31. Area Under Curves
The area bounded by the curve \(y^2=4 a(x-1)\) and the lines \(x=1, y=4 a\) is
- A \(\dfrac{16}{3} a^2 \text { squnits }\)
- B \(\dfrac{16}{3} a \text { sq units }\)
- C \(4 a^2 \text { sq units }\)
- D \(16 a^2 \text { squnits }\)
Answer & Solution
Correct Answer
(A) \(\dfrac{16}{3} a^2 \text { squnits }\)
Step-by-step Solution
Detailed explanation
The given curve is \(y^2 = 4a^2(x - 1)\). This can be rewritten as \(x - 1 = \dfrac{y^2}{4a^2}\), which implies \(x = \dfrac{y^2}{4a^2} + 1\). The area bounded by the curve, the line \(x = 1\), and the line \(y = 4a\) is the area between the curve and the y-axis (or vertical…
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