COMEDK · Maths · 33. Vector Algebra
The angle between the vectors \(\mathbf{a}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+2 \hat{\mathbf{k}}\) and \(\mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-2 \hat{\mathbf{k}}\) is
- A \(\sin ^{-1}(1 / 9)\)
- B \(\cos ^{-1}(8 / 9)\)
- C \(\sin ^{-1}(8 / 9)\)
- D \(\cos ^{-1}(1 / 9)\)
Answer & Solution
Correct Answer
(D) \(\cos ^{-1}(1 / 9)\)
Step-by-step Solution
Detailed explanation
We have, \(\mathbf{a}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}+2 \hat{\mathbf{k}}\) and \(\mathbf{b}=\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-2 \hat{\mathbf{k}}\) Clearly, \(|\mathrm{a}|=\sqrt{1+4+4}=\sqrt{9}=3\)…
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