COMEDK · Maths · 33. Vector Algebra
The angle between the vectors \(\mathrm{a}=\hat{\mathrm{i}}+2 \hat{\mathrm{j}}+2 \hat{\mathrm{k}}\) and \(\mathrm{b}=\hat{\mathrm{i}}+2 \hat{\mathrm{j}}-2 \hat{\mathrm{k}}\) is
- A \(\cos ^{-1}(1 / 9)\)
- B \(\sin ^{-1}(8 / 9)\)
- C \(\sin ^{-1}(1 / 9)\)
- D \(\cos ^{-1}(8 / 9)\)
Answer & Solution
Correct Answer
(A) \(\cos ^{-1}(1 / 9)\)
Step-by-step Solution
Detailed explanation
The angle \(\theta\) between two vectors \(\vec{a}\) and \(\vec{b}\) is given by the formula \(\cos \theta = \dfrac{\vec{a} \cdot \vec{b}}{|\vec{a}| |\vec{b}|}\). Given \(\vec{a} = \hat{i} + 2\hat{j} + 2\hat{k}\) and \(\vec{b} = \hat{i} + 2\hat{j} - 2\hat{k}\). Calculate the dot…
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