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COMEDK · Maths · 34. Three Dimensional Geometry

The angle between the lines \(\frac{x-2}{3}=\frac{y-1}{1}=\frac{z+3}{-1}\) and \(\frac{x+1}{2}=\frac{y-1}{-1}=\frac{z}{2}\) is

  1. A \(\cos ^{-1}\left(\frac{3}{\sqrt{11}}\right)\)
  2. B \(\sin ^{-1}\left(\frac{3}{\sqrt{11}}\right)\)
  3. C \(\cos ^{-1}\left(\frac{1}{\sqrt{11}}\right)\)
  4. D \(\sin ^{-1}\left(\frac{1}{\sqrt{11}}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\cos ^{-1}\left(\frac{1}{\sqrt{11}}\right)\)

Step-by-step Solution

Detailed explanation

Let, \(L_1 \equiv \frac{x-2}{3}=\frac{y-1}{1}=\frac{z+3}{-1}\) \(\therefore\) Direction ratio of \(L_1\left(l_1, m_1, n_1\right)=(3,1,-1)\) \(L_2 \equiv \frac{x+1}{2}=\frac{y-1}{-1}=\frac{z-0}{2}\) \(\therefore\) Direction ratio of \(L_2\left(l_2, m_2, n_2\right)=(2,-1,2)\)…
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