COMEDK · Maths · 27. Application of Derivatives
\(O A\) and \(O B\) are two roads enclosing an angle of \(120^{\circ} . X\) and \(Y\) start from \(O\) at the same time. \(X\) travels along \(O A\) with a speed of \(4 \mathrm{~km} / \mathrm{h}\) and \(Y\) travels along \(O B\) with a speed of \(3 \mathrm{~km} / \mathrm{h}\). The rate at which the shortest distance between \(X\) and \(Y\) is increasing after 1 hour is

- A \(37 \mathrm{~km} / \mathrm{h}\)
- B \(\sqrt{37} \mathrm{~km} / \mathrm{h}\)
- C \(\sqrt{13} \mathrm{~km} / \mathrm{h}\)
- D \(13 \mathrm{~km} / \mathrm{h}\)
Answer & Solution
Correct Answer
(B) \(\sqrt{37} \mathrm{~km} / \mathrm{h}\)
Step-by-step Solution
Detailed explanation
After time \(t\) hour distance covered by \(X\) and \(Y\) are \(4 t\) and \(3 t\) respectively. Now, shortest distance between \(X\) and \(Y\) after time t hour is given by…
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