COMEDK · Maths · 7. Binomial Theorem
Middle term of the expansion \(\left(x^2+\frac{1}{x^2}+2\right)^n\) is
- A \({ }^{2 n} C_n\)
- B \({ }^{2 n} C_{n+1}\)
- C \({ }^{4 n} C_n\)
- D \({ }^{4 n} C_{n+1}\)
Answer & Solution
Correct Answer
(A) \({ }^{2 n} C_n\)
Step-by-step Solution
Detailed explanation
We have, \(\left(x^2+\frac{1}{x^2}+2\right)^n=\left(x+\frac{1}{x}\right)^{2 n}\) Coefficient of middle term of \((x+y)^n\), if \(n\) is even \(={ }^n C_{n / 2}\) \(\Rightarrow\) Coefficient of middle term of \(\left(x+\frac{1}{x}\right)^{2 n}\)…
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