COMEDK · Maths · 11. Pair of Lines
Let the equation of pair of lines \(y=m_1 x\) and \(y=m_2 x\) can be written as
\(\left(y-m_1 x\right)\left(y-m_2 x\right)=0\). Then, the equation of the pair of the angle bisector of the line \(3 y^2-5 x y-2 x^2=0\) is
- A \(x^2+5 x y-y^2=0\)
- B \(x^2-5 x y+y^2=0\)
- C \(x^2-x y+y^2=0\)
- D \(x^2+x y-y^2=0\)
Answer & Solution
Correct Answer
(D) \(x^2+x y-y^2=0\)
Step-by-step Solution
Detailed explanation
\(\because\) Equation of angles of bisector of pair of straight line, \(a x^2+2 b x y+b y^2\) is \(\frac{x^2-y^2}{a-b}=\frac{x y}{h}\) \(\therefore\) For, \(3 y^2-5 x y-2 x^2=0\) \(a=3, b=-2, h=-5\) So, equation of angle bisector is…
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