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COMEDK · Maths · 5. Sequences and Series

Let '\(a\)' and '\(b\)' be two numbers where \(a < b\). The geometric mean of these numbers exceeds the smaller number by 12 and the arithmetic mean is smaller than the larger number by 24. Then the value of \(|b - a|\) is:

  1. A \(60\)
  2. B \(44\)
  3. C \(52\)
  4. D \(48\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(48\)

Step-by-step Solution

Detailed explanation

Given \(a < b\). The geometric mean exceeds the smaller number by \(12\): \(\sqrt{ab} = a + 12\) The arithmetic mean is smaller than the larger number by \(24\): \(\dfrac{a+b}{2} = b - 24\) \(a + b = 2b - 48\) \(b - a = 48\) Since \(a < b\), we have \(|b - a| = 48\). To verify,…
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