COMEDK · Maths · 10. Straight Lines
Let \(a\) and \(b\) be non-zero real such that \(a \neq b\).
Then, the equation of the line passing through the origin and the point of intersection of \(\frac{x}{a}+\frac{y}{b}=1\) and \(\frac{x}{b}+\frac{y}{a}=1\) is
- A \(a x+b y=0\)
- B \(b x+a y=0\)
- C \(y-x=0\)
- D \(x+y=0\)
Answer & Solution
Correct Answer
(C) \(y-x=0\)
Step-by-step Solution
Detailed explanation
Given, equation of lines are…
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