COMEDK · Maths · 27. Application of Derivatives
Length of the subtangent at \((a, a)\) on the curve \(y^{2}=\frac{x^{2}}{2 a+x}\) is equal to
- A \(\frac{18}{5}\)
- B \(\frac{18 a}{5}\)
- C \(-\frac{18 a^{2}}{5}\)
- D \(\frac{18 a^{2}}{5}\)
Answer & Solution
Correct Answer
(D) \(\frac{18 a^{2}}{5}\)
Step-by-step Solution
Detailed explanation
\(y^{2}=\frac{x^{2}}{2 a+x}\) \(2 y \frac{d y}{d x}=\frac{2 x}{2 a+x}-\frac{x^{2}}{(2 a+x)^{2}}\) At \((a, a),\left(\frac{d y}{d x}\right)_{(a, a)}=\frac{5}{18 a}\) Length of subtangent at…
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