COMEDK · Maths · 7. Binomial Theorem
In the expansion of \(\left(1-3 x+3 x^2-x^3\right)^{2 n}\), the middle term is
- A \((n+1)\) th term
- B \((2 n+1)\) th term
- C \((3 n+1)\) th term
- D None of these
Answer & Solution
Correct Answer
(C) \((3 n+1)\) th term
Step-by-step Solution
Detailed explanation
The given expression is \(\left(1-3x+3x^2-x^3\right)^{2n}\). Observe that \(1-3x+3x^2-x^3 = (1-x)^3\). Substituting this into the expression, we get \(\left((1-x)^3\right)^{2n} = (1-x)^{6n}\). The expansion of \((1-x)^{6n}\) has \(6n+1\) terms. The middle term of an expansion…
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