COMEDK · Maths · 36. Probability
In a trial, the probability of success is twice the probability of failure. In six trials, the probability of at most two failure will be
- A \(\frac{600}{729}\)
- B \(\frac{500}{729}\)
- C \(\frac{400}{729}\)
- D \(\frac{496}{729}\)
Answer & Solution
Correct Answer
(D) \(\frac{496}{729}\)
Step-by-step Solution
Detailed explanation
Let the probability of failure and success be \(p\) and \(q\), respectively. Let \(X\) represents the number of failure According to the question, \(q=2 p\) \(\because \quad p+q=1 \text { and } q=2 p\) \(\therefore \quad p=\frac{1}{3} \text { and } q=\frac{2}{3}\) Now, required…
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