COMEDK · Maths · 36. Probability
In a trial, the probability of success is twice the probability of failure. In six trials, the probability of at most two failure will be
- A \(\dfrac{600}{729}\)
- B \(\dfrac{400}{729}\)
- C \(\dfrac{500}{729}\)
- D \(\dfrac{496}{729}\)
Answer & Solution
Correct Answer
(D) \(\dfrac{496}{729}\)
Step-by-step Solution
Detailed explanation
Let \(p\) be the probability of success and \(q\) be the probability of failure. Given \(p = 2q\). Since \(p + q = 1\), we have \(2q + q = 1\), which implies \(3q = 1\), so \(q = \dfrac{1}{3}\) and \(p = \dfrac{2}{3}\). The number of trials is \(n = 6\). We want the probability…
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