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COMEDK · Maths · 26. Differentiation

\(\text { If } y=f(x), \quad p=\dfrac{d y}{d x} ; q=\dfrac{d^2 y}{d x^2} \text { then } \dfrac{d^2 x}{d y^2} \text { is equal to }\)

  1. A \(\dfrac{q}{p^2}\)
  2. B \(-\dfrac{q}{p^3}\)
  3. C \(\dfrac{q}{p}\)
  4. D \(-\dfrac{q}{p^2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-\dfrac{q}{p^3}\)

Step-by-step Solution

Detailed explanation

Given \(p = \dfrac{dy}{dx}\), we have \(\dfrac{dx}{dy} = \dfrac{1}{p} = p^{-1}\). Differentiating both sides with respect to \(y\) using the chain rule: \(\dfrac{d^2x}{dy^2} = \dfrac{d}{dy} \left( p^{-1} \right) = \dfrac{d}{dx} \left( p^{-1} \right) \cdot \dfrac{dx}{dy}\)…