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COMEDK · Maths · 23. Inverse Trigonometric Functions

If \(y=\tan ^{-1}\left(\frac{a-x}{1+a x}\right)\), then \(\frac{d y}{d x}=\)

  1. A \(\frac{1}{\left(1+x^{2}\right)}\)
  2. B \(\frac{a}{\left(1+a x^{2}\right)}\)
  3. C \(-\frac{1}{\left(1+x^{2}\right)}\)
  4. D \(\frac{x}{\left(1+x^{2}\right)}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(-\frac{1}{\left(1+x^{2}\right)}\)

Step-by-step Solution

Detailed explanation

Given, \(y=\tan ^{-1}\left(\frac{a-x}{1+a x}\right)\) \[ \Rightarrow \quad y=\tan ^{-1} a-\tan ^{-1} x \] Taking derivative w.r.t. \(x\) on both sides, we get \[ \frac{d y}{d x}=-\frac{1}{1+x^{2}} \]