COMEDK · Maths · 2. Quadratic Equation
If \(x = 4\) is a root of \(\begin{vmatrix} x & 3 \\ 1 & x - 2 \end{vmatrix} = 5\), then the other root is:
- A \(-1\)
- B \(-2\)
- C \(3\)
- D \(-4\)
Answer & Solution
Correct Answer
(B) \(-2\)
Step-by-step Solution
Detailed explanation
Expanding the given determinant, we get \(x(x - 2) - 3(1) = 5\) \(x^2 - 2x - 3 = 5\) \(x^2 - 2x - 8 = 0\) Factoring the quadratic equation, we get \((x - 4)(x + 2) = 0\) The roots are \(x = 4\) and \(x = -2\). Since \(x = 4\) is given as one root, the other root is \(-2\).…
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