COMEDK · Maths · 34. Three Dimensional Geometry
If two lines \(L_1: \frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}\) and \(L_2: \frac{x-3}{1}=\frac{y-k}{2}=z\) intersect at a point, then \(2 k\) is equal to
- A 9
- B \(\frac{1}{2}\)
- C \(\frac{9}{2}\)
- D 1
Answer & Solution
Correct Answer
(A) 9
Step-by-step Solution
Detailed explanation
Let \(\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{4}=\lambda\) Now, any point \(P\) that lies on the lines \(L_1\) has the form \((1+2 \lambda,-1+3 \lambda, 1+4 \lambda)\). Now, on putting \(x=1+2 \lambda, y=-1+3 \lambda\) and \(z=1+4 \lambda\) into the equation of lines \(L_2\), we…
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